I have tried to recognize what the oxidation state because that Mn in $ceMnO4^-$ is. So far i have construed that O have the oxidation state the -2 so due to the fact that there is 4 O the number transforms to -8. What wake up to the minus at O? and also what is the oxidation state for Mn?

The amount of the oxidation says of all of the atoms demands to same the full charge ~ above the ion.

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For example, for $ceNH4+$, if every hydrogen atom has actually an oxidation state that +1, and the overall charge is +1, climate we have the right to solve for the oxidation state of nitrogen:

eginaligned 4(+1) + OS_ceN &= +1\OS_ceN &= +1 -4(+1) \OS_ceN &= -3endaligned

Similarly, we have the right to do $ceSO4^2-$. If each oxygen atom has actually an oxidation state that -2, and the in its entirety charge is -2, we can solve because that the oxidation state the sulfur:

eginaligned 4(-2) + OS_ceS &= -2\OS_ceS &= -2 -4(-2) \OS_ceS &= +6endaligned

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answered january 6 "19 in ~ 12:28

Ben NorrisBen Norris
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Seeing together Oxygen has an oxidation state of -2 and you have actually 4 Oxygen atoms, the total charge added by Oxygen = -8. Since the total charge of this compound = -1, then in this case Mn = +7+7 - 8 = -1

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answered january 6 "19 in ~ 13:32

PeteLDWPeteLDW
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As you said Oxygen has the oxidation state of -2 so if we include up every the oxygens they have actually a -8 oxidation state.

As the oxidation state that the ion is equal to that charge, the Mn needs to "balance" the -8 to obtain it up to -1. Because of this the oxidation state that Mn in Mno4- is +7.

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answered jan 6 "19 at 13:33

LR01LR01
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