Where ns is the perimeter, ns is the length of the rectangle, and w is the broad of the rectangle.
You are watching: P 21 2w solve for w
Rearrange the equation to solve for i (length), then use your equation to find the length of a rectangle v a perimeter the 12cm and also a broad of 2.5cm.
(Show your equation and your solution.)
The formula because that the perimiter that a rectangle is ns = 2l + 2w. The concern is asking united state to fix for l in this formula. In bespeak to carry out that, we execute the following:
p = 2l + 2wSubtract 2w to the other side to isolate l
p - 2w = 2lDivide through 2 to deal with for l
l = (p - 2w)/2
Now we have to use this equation to resolve for together if p = 12 cm and also w = 2.5 cm
l = (p - 2w)/2Let"s plugin our values first
l = (12 - (2 * 2.5))/2Let"s main point 2 through 2.5 to obtain 5
l = (12 - 5)/2Now subtract 12 through 5 to acquire 7
l = 7/2Now division 7 by 2 to gain 3.5
l = 3.5 cm
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