### (b^2-2b-8)/(b^2+b-2)-6/(b-1)

This encounters simplification or other basic results.

You are watching: Simplify the difference b^2-2b-8

## Step by action Solution

## Step 1 :

6 simplify ————— b - 1Equation at the end of step 1 : (((b2)-2b)-8) 6 —————————————-——— (((b2)+b)-2) b-1## Step 2 :

b2 - 2b - 8 simplify ——————————— b2 + b - 2 make the efforts to variable by dividing the middle term2.1Factoring b2 - 2b - 8 The first term is, b2 the coefficient is 1.The middle term is, -2b that is coefficient is -2.The last term, "the constant", is -8Step-1 : multiply the coefficient the the first term through the consistent 1•-8=-8Step-2 : discover two factors of -8 who sum equals the coefficient that the center term, i beg your pardon is -2.-8 | + | 1 | = | -7 | ||

-4 | + | 2 | = | -2 | That"s it |

Step-3 : Rewrite the polynomial dividing the middle term utilizing the two factors found in step2above, -4 and 2b2 - 4b+2b - 8Step-4 : add up the first 2 terms, pulling out favor factors:b•(b-4) include up the critical 2 terms, pulling out common factors:2•(b-4) Step-5:Add up the 4 terms that step4:(b+2)•(b-4)Which is the wanted factorization

Trying to factor by dividing the center term2.2Factoring b2+b-2 The very first term is, b2 the coefficient is 1.The middle term is, +b that coefficient is 1.The last term, "the constant", is -2Step-1 : main point the coefficient of the an initial term by the constant 1•-2=-2Step-2 : uncover two components of -2 who sum amounts to the coefficient the the middle term, which is 1.

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-2 | + | 1 | = | -1 | ||

-1 | + | 2 | = | 1 | That"s it |

Step-3 : Rewrite the polynomial separating the center term making use of the two components found in step2above, -1 and also 2b2 - 1b+2b - 2Step-4 : include up the very first 2 terms, pulling out favor factors:b•(b-1) include up the critical 2 terms, pulling out common factors:2•(b-1) Step-5:Add up the four terms of step4:(b+2)•(b-1)Which is the preferred factorization

Canceling out :2.3 Cancel the end (b+2) which shows up on both political parties of the fraction line.

Equation at the end of step 2 :(b - 4) 6 ——————— - ————— b - 1 b - 1

## Step 3 :

Adding fountain which have a usual denominator :3.1 adding fractions which have a typical denominatorCombine the molecule together, placed the sum or distinction over the typical denominator then mitigate to lowest terms if possible:(b-4) - (6) b - 10 ——————————— = —————— b-1 b - 1