The huge Screamer Coaster dead 92 human being altogether. Several of its cars bring 4 passengers, and also the rest carry 6 passengers. There room 3 an ext 4 passenger cars then 6 passenger cars. How numerous 4 passenger cars space there? Anybody have a clue?

There are 8 6-passenger cars the can bring 8 X 6=48 people

Therefore, there space 8 + 3=11, 4-passenger dare that have the right to carry: 11 X 4=44 people,

Because: 48 + 44=92people in total.

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There are 8 6-passenger cars the can bring 8 X 6=48 people

Therefore, there room 8 + 3=11, 4-passenger cars that deserve to carry: 11 X 4=44 people,

Because: 48 + 44=92people in total.

+121057

The big Screamer Coaster tote 92 human being altogether. Several of its cars lug 4 passengers, and the rest lug 6 passengers. There room 3 an ext 4 passenger cars then 6 passenger cars. How numerous 4 passenger cars space there? Anybody have actually a clue?

Let x it is in the number of 4 passenger cars.......then x- 3 is the variety of 6 passenger cars....and us have

4x + 6(x - 3) = 92 simplify

4x + 6x - 18 = 92

10x - 18 = 92 add 18 to both sides

10x = 110 divide both sides by 10

x = 11 and this is the variety of 4 passenger cars

CPhill Sep 22, 2015

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