I thought it to be correct since sqrt is opposing of multiplying by a number, so ns figured by multiplying by a number it would certainly balance out and also be that number normally, however when i tried it through my Python calculator making use of 3 i got:

6294.org.sqrt(3) * 3 5.196152422706632


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$egingroup$ $sqrt x$ is the number satisfying $sqrt x sqrt x = x$; it's no the the opposite of multiply by $x$. $endgroup$
In general, no. Since $sqrt x$ is same to $x^1/2$, her equation is the same as $x^3/2 = x$, just $x = 0, 1$ occupational as solutions


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If you want to solve for the equation$$xsqrtx = x$$then you have$$x (sqrtx-1) =0 Rightarrow x = 0, ext or sqrtx=1, ext i.e. x = 1$$


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The multiplicative train station (the "opposite" in your question) that a non-zero number $x$ is that reciprocal, $frac1x$. Multiplying these two together offers instead $x imes frac1x = 1$.

You are watching: What is x times root x


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calculate the the border of the sequence $a_n = lim_n o infty n^frac23cdot ( sqrtn-1 + sqrtn+1 -2sqrtn )$
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